Q 1 :    

Which of the following complex is homoleptic?                              [2024]

  • [Ni(CN)4]2-

     

  • [Ni(NH3)2Cl2]

     

  • [Fe(NH3)4Cl2]+

     

  • [Co(NH3)4Cl2]+

     

(A)

Complexes in which a metal is bound to only one kind of donor groups are known as homoleptic. Complexes in which a metal is bound to more than one kind of donor groups are known as heteroleptic. (1) is homoleptic. (2), (3) and (4) are heteroleptic.

 



Q 2 :    

The correct IUPAC name of [PtBr2(PMe3)2] is:                     [2024]

  • dibromobis(trimethylphosphine)platinum(II)

     

  • bis[bromo(trimethylphosphine)]platinum(II)

     

  • dibromodi(trimethylphosphine)platinum(II)

     

  • bis(trimethylphosphine)dibromoplatinum(II)

     

(A)

Multiplicity of simple ligands is denoted by di, tri, tetra etc. and multiplicity of complex ligands is denoted by bis, tris, tetrakis etc.

[Pt+2 Br2 -1(PMe03)2] : dibromobis (trimethylphosphine) platinum(II)

 



Q 3 :    

Given below are two statements:

 

Statement I: N(CH3)3 and P(CH3)3 can act as ligands to form transition metal complexes.

 

Statement II: As N and P are from the same group, the nature of bonding of N(CH3)3 and P(CH3)3 is always same with transition metals.

 

In the light of the above statements, choose the most appropriate answer from the options given below:                      [2024]

  • Statement I is correct but Statement II is incorrect

     

  • Both Statement I and Statement II are correct

     

  • Statement I is incorrect but Statement II is correct

     

  • Both Statement I and Statement II are incorrect

     

(A)

Since both N and P have lone pair of electrons in N(CH3)3 and P(CH3)3, these act as ligands and form complexes. P has vacant d orbital hence P(CH3)3 act as π acceptor ligand, but N(CH3)3 cannot do so as N does not have a vacant d orbital.